What is the stoichiometric A F ratio for the combustion of methane CH4 on mass basics?
Stoichiometric air-to-fuel ratios of common fuels
| Fuel | Ratio by mass | Main reaction |
|---|---|---|
| Methane | 17.19 : 1 | CH 4 + 2 O 2 → CO 2 + 2 H 2O |
| Acetylene | 13.26 : 1 | 2 C 2H 2 + 5 O 2 → 4 CO 2 + 2 H 2O |
| Ethane | 16.07 : 1 | 2 C 2H 6 + 7 O 2 → 4 CO 2 + 6 H 2O |
| Butane | 15.44 : 1 | 2 C 4H 10 + 13 O 2 → 8 CO 2 + 10 H 2O |
How much air is required for combustion?
Therefore the quantity of oxygen required for combustion of 1 kg of the fuel is: (2.66C + 8H + S) kg. ∴ Oxygen required from air for the complete combustion of fuel will be (2.66C + 8H + S – O) which can be written as 2.66C + 8 (H – O/8) + S, the term in the bracket being known as the available hydrogen.
How do you calculate gas to flue ratio?
Calculating the Ratio
- So 1 molecule of methane has a molecular weight of: 1 * 12.01 + 4 * 1.008 = 16.042.
- One oxygen molecule weighs: 2 * 16 = 32.
- The oxygen-fuel mass ratio is then: 2 * 32 / 1 * 16.042 = 64 / 16.042.
- So we need 3.99 kg of oxygen for every 1 kg of fuel.
What is the most efficient mixture ratio of fuel to air?
14.7:1
14.7:1 is perfect for idle and light throttle cruising conditions as it’s the most efficient mixture possible, meaning the best fuel economy and lowest emissions.
What is the chemical equation for combustion of methane CH 4?
The chemical equation for stoichiometric combustion of methane – CH 4 – with air can be expressed as If more air is supplied some of the air will not be involved in the reaction. The additional air is termed excess air, but the term theoretical air may also be used. 200% theoretical air is 100% excess air.
What is the air to fuel ratio for methane?
• It can be seen that the complete combustion of one volume of methane will require (2+7.52=9.52) volumes of air, so the stoichiometric air-to-fuel (A/F) ratio for methane is 9.52.
Which is the most common oxidizer in methane combustion?
Example – Stoichiometric Combustion of Methane – CH 4 The most common oxidizer is air. The chemical equation for stoichiometric combustion of methane – CH 4 – with air can be expressed as CH4 + 2 (O2 + 3.76 N2) -> CO2 + 2 H2O + 7.52 N2
How is the stoichiometric ratio used in the combustion process?
The combustion process can be expressed: To determine the excess air or excess fuel for a combustion system we starts with the stoichiometric air-fuel ratio. The stoichiometric ratio is the perfect ideal fuel ratio where the chemical mixing proportion is correct.